I know I'm not neutralizing the user above me, but Sishen did a bad job of neutralizing Chaika. I have used science and mathematics to propose a solution.
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Chaikaic Acid is a very strong acid (it is similar to hydroiodic acid). Because Chaika has 13 moles on them, and after some quick research, I found that the average human has a volume of about 66.4 Liters. Thus, Chaika's molarity is about 0.196 M.
The only thing we have for titrations here in the Sandbox is urea, which is a weak base (roughly a pH of 9.5). Of course, the urea is very concentrated, and I measured it to be a 10 M stock solution of urea.
Because Chaikaic Acid is a strong acid, titrating it with a weak base (urea) is tough. However, through my calculations (and this website:
http://www.chemistryshark.com/calculator/titration/), I have deduced that to achieve a final pH of 7, one needs about 8676 L of urea.
Thus, I ask that Sandbox produces 8676 L of 10 M urea in order to neutralize Chaika.
Thank you.