Thanks everyone your loyal your geniuses stay blessed

FancyStance says

its 0.051 becuase you have to multiply it by 2

Correct. 0.0507 rounds to 0.051 not 0.05.

Our bad.

its 0.051 becuase you have to multiply it by 2

Calvin says

they don't want you to pitch!

bless up!

lmao

@The, you put the decimal in the wrong spot. It's 0.025 m/s not 0.25. But your formulas are right.

My only guess for where the 0.013 comes from, is if the mass of each canoe is 60 KGs (120 total weight not 120 each), then each canoe moves at 0.013 afterwards.

edit: you corrected yourself right before I did. lol

Update
I lost a decimal place by accident, so it's actually 0.05 m/s ( 0.025 * 2)

joshua says

The answer also comes up in Google, so I mean.

Yeah, except the top one in the search results is wrong. They only account for the first (explosive) collision, and not the second collision when the other canoeist catches the ball.

The answer also comes up in Google, so I mean.

p= 0.145kg ∗ 21m/s

p = 120kg * v

solve for v

i think, idk its been awhile since ive done anything like this.

This problem utilizes knowledge of the law of conservation of momentum.

1st collision: the throw (explosive collision)
0 = (.145)(21) + (120)(v)
v (of 1st canoeist) = - 0.25 m/s

2nd collision: the catch (sticky collision)
(.145)(21) + 0 = v(120 + .145)
v (of 2nd canoeist) = 0.25 m/s

So then if the canoes are moving in opposite directions both at 0.25 m/s, then the distance between them is increasing at approximately 0.5 m/s.

Don't know where you got 0.013 m/s from.

Who the f*ck do that anyway?

Bless up Calvin Win more

they don't want you to pitch!

bless up!