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Puzzle (not a riddle)

almost 10 years

Ok this is not my puzzle. But while I create one, here is my variant of an old puzzle

You have a deck of 28 cards

8, 9, 10, J, Q, K, A for each suit

you have to arrange to arrange 25 of these cards in the following manner

[] [] [] [] []

[] [] [] [] []

[] [] [] [] []

[] [] [] [] []

[] [] [] [] []

Such that each row, each column, each diagonal is one of the following poker hands.

  1. One pair
  2. Two pair
  3. Three of a kind
  4. Straight
  5. Flush
  6. Full house
  7. Straight flush
  8. Royal flush
  9. Four of a kind

It is a must that all the above hands are there in the arrangement at least once.

There can be multiple such arrangements.

almost 10 years
AKK8A
J99JJ
11A11
QQQAK
KJ88Q

first 3 columns are flushed
almost 10 years
nerds
almost 10 years
im assuming you meant like "you can make 2 royal flushes and count one as a flush"
almost 10 years
KK88K
J99AA
11911
QQ98Q
AJ8JQ

first two columns are flushed
almost 10 years
actually its really easy if you can use royal flush as flush and straight
almost 10 years
you can use royal flush for flush and straight? not straight flush though im guessing? bc that would be incredibly easy
almost 10 years
you can use royal flush as flush and straight. But your second row does not make any of the given named poker hands.
almost 10 years
I think putting the royal flush diagonally is the best chance but I'm not doing this again for now lol

Edit nvm then you can't get a flush also
almost 10 years
1♦ J♦ Q♦ K♦ A♦
9♥ Q♣ 1♥ K♣ A♥
9♦ A♠ Q♥ K♥ 8♥
9♣ A♣ 1♣ K♠ 8♦
8♠ 9♠ 1♠ J♠ Q♠

1=10

Did this and then realized you can't use a Royal Flush as a Straight, Straight Flush, Flush, and Royal Flush all at the same time (Can you? If so I solved it)